0=0.06(x^2)+(2*x)=250

Solution for 0=0.06(x^2)+(2*x)=250 equation:

0=0.06(x^2)+(2x)=250

We move all terms to the left:

0-(0.06(x^2)+(2x))=0

We add all the numbers together, and all the variables

-(0.06x^2+2x)=0

We get rid of parentheses

-0.06x^2-2x=0

a = -0.06; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-0.06)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-0.06}=\frac{0}{-0.12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-0.06}=\frac{4}{-0.12}
=-33+0.04/0.12
$